**Contents**show

## How many ways can get sum of 5 when you roll two dice at the same time?

We can get a sum of 5 in **two different combinations** also: (1,4) and (2,3). Why is it that in de Mere’s practice 5 appears more often than 4?

## What is the probability of getting 5 when two dice are thrown together?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

3 | 2 | 5.56% |

4 | 3 | 8.33% |

5 | 4 |
11.11% |

6 | 5 | 13.89% |

## What is the probability of getting a sum of 7 when rolling two dice?

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is **6/36 = 1/6**.

## What is the probability of rolling a sum of 10 on a standard pair of six sided dice?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

8 | 26/36 (72.222%) |

9 | 30/36 (83.333%) |

10 | 33/36 (91.667%) |

11 | 35/36 (97.222%) |

## What is the probability that the sum of two dice will yield a 4 or 6?

Thus P(two dice sum to either 4 or 6)=836=**29**.

## What is the probability of getting 1 and 5 If a dice is thrown once?

So they are mutually exclusive events, therefore their probabilities add to 1. By symmetry we expect that each face is equally likely to appear and so each has probability = **1/6**. The outcome of a 5 is one of those events and so has probability = 1/6 of appearing.

## What is the probability of rolling a 6 with 3 dice?

So, there are 125 out of 216 chances of a 6 NOT appearing when three dice are rolled. Simply subtract 125 from 216 which will give us the chances a 6 WILL appear when three dice are rolled, which is **91**. 91 out of 216 or 42.1 %.

## What is the probability of getting a sum of 22 Aur more when four dice are thrown?

⇒**6+6+6+4=22** , this arrangement is possible in 4 ways with different positions of numbers 4 to appear. Hence, the option (B) is the correct answer.